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int ia[] = { 0, 1, 2, 3, 4, 5 }; // shift left by one, resulting in {1,2,3,4,5,5} copy( ia+1, ia+6, ia );

locations of crossover randomly. As seen in the Figure 5.7, these locations are arbitrary gene boundary locations and at these locations the gene content from the two parents gets mixed. The offspring thus created now contains parts of the genes coming from the contributing parents. The motivation for this step is the fact that, as more and more generations pass, the ttest parents undergoing crossover will already contain the better sets of parameters, and their crossing might bring together the better sets of parameter values from both the parents. 5.5.1.6 Mutation

copy() begins at the second element of ia, copying 1 into the first slot, and so on until each element is copied to the slot on its left

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In addition to the process of crossover at gene boundaries in the chromosome, the values of some parameters within the genes might be changed randomly. This is illustrated in the Figure 5.8. Such mutations help in exploring the local parameter space more thoroughly. Mutations can be seen as small perturbations to the larger search that explores the vast parameter space, searching for the global minima.

#include <algorithm> #include <vector> #include <iterator> #include <iostreamh> /* generates: 0 1 1 3 5 8 13 shifting array sequence left by 1: 1 1 3 5 8 13 13 shifting vector sequence left by 2: 1 3 5 8 13 8 13 */ int main() { int ia[] = { 0, 1, 1, 3, 5, 8, 13 }; vector< int, allocator > vec( ia, ia+7 ); ostream_iterator< int > ofile( cout, " " ); cout "original element sequence:\n"; copy( vecbegin(), vecend(), ofile ); cout '\n'; // shift left by one copy( ia+1, ia+7, ia ); cout "shifting array sequence left by 1:\n"; copy( ia, ia+7, ofile ); cout '\n'; // shift left by two copy( vecbegin()+2, vecend(), vecbegin() ); cout "shifting vector sequence left by 2:\n"; copy( vecbegin(), vecend(), ofile ); cout '\n'; } copy_backward() template class BidirectionalIterator1, class BidirectionalIterator2 > BidirectionalIterator2 copy_backward( BidirectionalIterator1 first, BidirectionalIterator1 last1, BidirectionalIterator2 last2 );

copy_backward() behaves the same as copy() except that the elements are copied in the reverse order That is, copying begins at last1-1 and proceeds to first The elements are also copied into the target container backward, beginning with last2-1 and proceeding backward for last1-first elements For example, given the sequence {0,1,2,3,4,5}, we can copy the last three elements (3,4,5) into the first three (0,1,2) by setting first to the address of value 0, last1 to the address of value 3, and last2 to the address one past the value 5 Element value 5 is assigned to the previous element value 2, then element 4 to the previous element 1, and finally element 3 to the previous element 0 The resulting sequence is {3,4,5,3,4,5}

Popular EAP method types Type 23 25 26 32 38 43 46 191 192 255 Type UMTS Authentication and key agreement PEAP MS-EAP Authentication Secur ID EAP EAP-HTTP Digest EAP-FAST Available via review by Designated expert Reserved + Experimental

Most feature-based face recognition methods use feature detectors that are not tailored speci cally for face recognition, and they make no attempt to selectively choose feature detectors based speci cally on their usefulness for face recognition. The method

#include <algorithm> #include <vector> #include <iterator> #include <iostreamh> class print_elements { public:

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void operator()( string elem ) { cout elem ( _line_cnt++%8 " " : "\n\t" ); } static void reset_line_cnt() { _line_cnt = 1; } private: static int _line_cnt; }; int print_elements::_line_cnt = 1; /* generates: original list of strings: The light untonsured hair grained and hued like pale oak sequence after copy_backward( begin+1, end-3, end ): The light untonsured hair light untonsured hair grained and hued */ int main() { string sa[] = { "The", "light", "untonsured", "hair", "grained", "and", "hued", "like", "pale", "oak" }; vector< string, allocator > svec( sa, sa+10 ); cout "original list of strings:\n\t"; for_each( svecbegin(), svecend(), print_elements() ); cout "\n\n"; copy_backward( svecbegin()+1, svecend()-3, svecend() ); print_elements::reset_line_cnt(); cout "sequence after " < "copy_backward( begin+1, end-3, end ):\n"; for_each( svecbegin(), svecend(), print_elements() ); cout "\n"; } count() template< class InputIterator, class Type > iterator_traits<InputIterator>::distance_type count( InputIterator first, InputIterator last, const Type& value );

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